[xsl] problem with xsl:when test

Subject: [xsl] problem with xsl:when test
From: psahoo@xxxxxxxxxxx
Date: Fri, 30 Jan 2004 18:09:19 +0530




Hi
   Hope to get response to solve this
................................................
   I have cretaed a xls which read a xml , where the nodes are dynamic . So
for that I have written a when test statement in it to
check the node  type and depending upon the type (Struct_Element and
Array_Element ) of node I show it as a hyperlink . But I face the follwoing
problem ..

1. Suppose there is 3 (X ,Y and Z) nodes .Suppose X is of type
Array_Element and others are not of type Array_Element or Struct_Element  .
      But  at the end I am getting all X,Y and Z are  as hyperlink

BUT
  IF there will be no node of type  Array_Element or Struct_Element , it
gives perfect result .


version of xsl------------------------
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/TR/WD-xsl";>
-----------------------------------------------------------------------------------------------------

I am giving the sample code

<xsl:template match="//Output_List/*" >
                        <tr>
                              <td align="center"><xsl:value-of select="@Name" /></td>
                              <td align="center">
                                    <xsl:choose>
                                    <xsl:when test="//Output_List/*[nodeName()='Struct_Element' or nodeName()='Array_Element']">
                                          <A href="datatypes.xml"><xsl:value-of select="@Type" /></A>
                                    </xsl:when>
                                    <xsl:otherwise>
                                          <xsl:value-of select="@Type" />
                                    </xsl:otherwise>
                                    </xsl:choose>
                              </td>
                              <td align="center"><xsl:value-of select="@Comment" /></td>
                        </tr>
      </xsl:template>

Thanks & Regards
Prasanta



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