RE: [xsl] XPath statement for traversing a nested node structure

["Kenny Akridge" <kakridge@xxxxxxxxxxxxx>]

Scott,

When I use this XML:

<TABLE>
	<DPROW>
		<OBJECT>1</OBJECT>
		<TABLE>
			<DPROW>
				<OBJECT>2</OBJECT>
				<OBJECT>3</OBJECT>
				<OBJECT>4</OBJECT>
				<TABLE>
					<DPROW>
						<OBJECT>5</OBJECT>
						<OBJECT>6</OBJECT>
						<OBJECT>7</OBJECT>
						<OBJECT>8</OBJECT>
						<OBJECT>9</OBJECT>
					</DPROW>
				</TABLE>
			</DPROW>
		</TABLE>
		<TABLE>
			<DPROW>
				<OBJECT>10</OBJECT>
				<OBJECT>11</OBJECT>
				<OBJECT>12</OBJECT>
				<OBJECT>13</OBJECT>
				<TABLE>
					<DPROW>
						<OBJECT>14</OBJECT>
						<OBJECT>15</OBJECT>
						<OBJECT>16</OBJECT>
						<OBJECT>17</OBJECT>
						<OBJECT>18</OBJECT>
						<OBJECT>19</OBJECT>
					</DPROW>
				</TABLE>
				<TABLE>
					<DPROW>
						<OBJECT>20</OBJECT>
						<OBJECT>21</OBJECT>
						<OBJECT>22</OBJECT>
						<OBJECT>23</OBJECT>
						<OBJECT>24</OBJECT>
						<OBJECT>25</OBJECT>
						<OBJECT>26</OBJECT>
						<OBJECT>27</OBJECT>
						<OBJECT>28</OBJECT>
					</DPROW>
				</TABLE>
			</DPROW>
		</TABLE>
	</DPROW>
</TABLE>
and either of the templates I provided...

I get 1 3 5 4 6 9 as output.

I think the problem is that we did not have an agreement of the tree
traversal order.  My algorithm is a preorder traversal, and you may
want inorder or postorder.  Look at how I have the objects numbered and
change it to include the order you want.  This is where we may have to
use recursion.


-----Original Message-----
From: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx
[mailto:owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx] On Behalf Of scott
gabelhart
Sent: Wednesday, February 04, 2004 5:30 PM
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: Re: [xsl] XPath statement for traversing a nested node
structure

Kenny Akridge wrote:

>If you are looking for a simple count of each object within a node(not
a
>sum of objects that includes the table subnode), then both of these
will
>work:
>
><?xml version="1.0"?>
><xsl:stylesheet version="1.0"
>xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
><xsl:template match="/">
>	<xsl:for-each select="//TABLE">
>		<xsl:value-of select="concat(count(DPROW/OBJECT),
>'&#160;')"/>
>	</xsl:for-each>
></xsl:template>
></xsl:stylesheet>
>
><?xml version="1.0"?>
><xsl:stylesheet version="1.0"
>xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
><xsl:template match="/">
>	<xsl:apply-templates select="//TABLE"/>
></xsl:template>
>
><xsl:template match="TABLE">
>	<xsl:apply-templates select="DPROW"/>
></xsl:template>
>
><xsl:template match="DPROW">
>	<xsl:value-of select="concat(count(OBJECT), '&#160;')"/>
></xsl:template>
></xsl:stylesheet>
>
>However, if you need the sum then you will need to use some
>recurision(off hand this is what I am thinking).
>
>I think your problem with DPROW/OBJECT is that you are getting a count
>based on the first table context.
>
>-----Original Message-----
>From: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx
>[mailto:owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx] On Behalf Of scott
>gabelhart
>Sent: Wednesday, February 04, 2004 2:40 PM
>To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
>Subject: [xsl] XPath statement for traversing a nested node structure
>
>I need some assistance with traversing a nested xml input file
>structure.
>
>I need to determine between the begining of one nested structure and 
>another the number of occurances of a particular element.
>
>Example:
>
><TABLE><DPROW><OBJECT></OBJECT></DPROW></TABLE> would yield an
occurance
>
>of one OBJECT element using the XPath statement DPROW/OBJECT.
>
>The above XPath statement falls apart though when I introduce nested 
>structures.
>
><TABLE><DPROW><OBJECT></OBJECT><TABLE><DPROW><OBJECT></OBJECT><OBJECT><
/
>OBJECT></DPROW></TABLE></DPROW></TABLE>
>Inner most TABLE element has two OBJECT elements and the outer TABLE 
>element would yield one OBJECT element.
>
>What is a valid XPath statement need for traversing the nested xml 
>structure above?
>
>Any help would be greatly appreciated.
>
>- Scott
>
> XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
>
>
> XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
>
>
>  
>
Kenny running your second xsl example gets me closer; but still run into

error after the third nested table structure.

Here is the output 
1Â 2Â 15Â 14Â 10Â 6Â 13Â 14Â 4Â 16Â 1Â 1Â 1Â 1Â 1Â 1Â 1Â 1Â 12Â 10Â 10Â
10Â 10Â 10Â 10Â 10Â 10Â 10Â 9Â 10Â 10Â 10Â 10Â 10Â 10Â 10Â 10Â 10Â 


Based upon my xml structure the 14^A should only be returning 3 ^A.

Also can you include a recursive example. I have never used recursion in

my transforms before.

Thanks in advance.

- Scott


- Scott

 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list


 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list