Re: [xsl] Apply Template based on position or count

["Karl J. Stubsjoen" <karl@xxxxxxxxxxxxx>]

I'm a bit stuck.  Please see these results:
http://www.meetscoresonline.com/results.asp?tax=3&meet=10027


Notice, 2 columns, 3 rows.  Correctly, there is no data for the last item
(bottom right).
Incorrectly, the z:row template is applied and we end up with what you see
(empty results).  Nothing should appear at all.
So.. test for string() possibly?  Nope, that didn't work.
Well here is what I have:

<xsl:choose>
  <xsl:when test="following::node()[1]"><xsl:apply-templates
select="following::node()[1]" mode="session_info"/></xsl:when>
  <xsl:otherwise>&nbsp;</xsl:otherwise>
</xsl:choose>

Thanks.

----- Original Message -----
From: "David Carlisle" <davidc@xxxxxxxxx>
To: <xsl-list@xxxxxxxxxxxxxxxxxxxxxx>
Sent: Friday, February 06, 2004 3:34 PM
Subject: Re: [xsl] Apply Template based on position or count


>
>               <xsl:for-each select="xml/rs:data/z:row">
>                     <xsl:if test="position() mod 2 = 1">
>                     <xsl:if test=".">
>
>
> That last xsl:if is not testing anything it will always be true.
> A node set in a boolean context is true if it is non empty and the node
> set selected by . always has size one so is never empty.
>
> David
>
> --
> http://www.dcarlisle.demon.co.uk/matthew
>
>  XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
>
>


 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list