Subject: Re: [xsl] concating strings in a loop From: Herwig Posedu <herwig.posedu@xxxxxxxxxx> Date: Tue, 10 Feb 2004 15:34:17 +0100 |
thank u - it works perfectly :)hi!
i want to display a list of persons "comma-seperarted" on my pdf-file. how can i concate those person-names seperated with a "," but in that way, that after the last name is no ",".
i did it like this
<xsl:for-each select="person">
<xsl:value-of select="name" />
,<fo:inline color="white">.</fo:inline>
</xsl:for-each>
-> the output for example is: mike, john,
-> i want to have: mike, john
how can i concate the strings and substring it, so that the last comma will be removed
If your date looks like this:
<person> <name>mike</name> </person> <person> <name>john</name> </person>
The instruction <xsl:for-each select="person"> will select a list of 2 nodes to process. The function position() will give you the position of the node you are currently processing in the list, and last() will give you the position of node that's last in the list. So, you only want to output a comma if the position of the node you are processing is not the last one:
<xsl:if test="position() != last()">, </xsl:if>
cheers andrew
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
-- Herwig Posedu
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