Subject: Re: [xsl] Value at position() From: David Carlisle <davidc@xxxxxxxxx> Date: Tue, 10 Feb 2004 14:50:52 GMT |
Despite the fact that the subject line contains "position()" you do not want the position() function, the value returned by position() has _no relation_ to the location of the element in the source tree. It relates to the position of the node in the current node list, which is determined by the currently active select=... For example any element selected by parent::* will have position() of 1. The same element selected by a different Xpath will usually have a different position(). > A is found at element 4. If you really need that (which is unlikely) then you want to know the number which is one more than teh number of earlier siblings of that element, which is: <xsl:value-of select="count(*[.='A']/preceding:-sibling::*) + 1"/> However if you just want to select the element with value A you do not need this number, you just need select="*[.='A']" David -- http://www.dcarlisle.demon.co.uk/matthew ________________________________________________________________________ This e-mail has been scanned for all viruses by Star Internet. The service is powered by MessageLabs. For more information on a proactive anti-virus service working around the clock, around the globe, visit: http://www.star.net.uk ________________________________________________________________________ XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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