RE: [xsl] Counting nodes efficiently

["Andrew Welch" <AWelch@xxxxxxxxxxxxxxx>]

I wrote:

> 1.  Create a node-set by selecting all the elements you wish 
> to count and numbering them using position().  You can then 
> query into this node-set using the generate-id() function to 
> get the correct number for the element you're processing.  
> This only requies one pass of the data so its quite efficient.
> 
> 2.  Write a SAX Filter in java that numbers the elements on 
> their way into the transform.  You can then select this 
> number as if it was already in the data.
> 
> 3.  If you are using saxon, you can substring the value 
> returned from generate-id() after the 'e', as the generated 
> id's take form 'dxxeyy' where d is the document number and e 
> is the element number.

...having got the wrong end of the stick. (I guess I read the title more
than the post)

:-)

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