Subject: RE: [xsl] How Do I Select A Section of XML Based On A Code Value From: "Kenny Akridge" <kenny@xxxxxxxxxxxxxxxxx> Date: Wed, 25 Feb 2004 10:38:20 -0500 |
Something like this: <?xml version="1.0"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:template match="/"> <xsl:for-each select="//VehInfo[descendant::UsageInfoCode = 'Work']"> <xsl:element name="VehInfo"> <xsl:element name="ModelYear"> <xsl:value-of select="ModelYear"/> </xsl:element> <xsl:element name="Model"> <xsl:value-of select="Model"/> </xsl:element> </xsl:element> </xsl:for-each> </xsl:template> </xsl:stylesheet> -----Original Message----- From: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx [mailto:owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx] On Behalf Of Gary Fix Sent: Wednesday, February 25, 2004 10:17 AM To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx Subject: [xsl] How Do I Select A Section of XML Based On A Code Value Hi, I have an xml something like this: <VehInfo> <ModelYear>2004</ModelYear> <Model>Ford</Model> <UsageInfo> <UsageInfoCode>Work</UsageInfoCode> </UsageInfo> </VehInfo> <VehInfo> <ModelYear>1994</ModelYear> <Model>Toyota</Model> <UsageInfo> <UsageInfoCode>Pleasure</UsageInfoCode> </UsageInfo> </VehInfo> and want to transform this into xml using xsl, selecting the correct section based on the <UsageInfoCode> tag. For example, if I am to select using an "UsageInfoCode" of "Work", then I want the output xml to look like this: <VehInfo> <ModelYear>2004</ModelYear> <Model>Ford</Model> </VehInfo> Any help would be greatly appreciated! thanks....gary... XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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