Subject: RE: [xsl] reccursive sum ? From: "Ricaud Matthieu" <matthieu.ricaud@xxxxxxx> Date: Tue, 2 Mar 2004 14:38:48 +0100 |
Thanks a lot David for the explanations. I took the habit to use too much variables, and as I learnt xsl on my own, nobody told me about this (and many other things for sure). So really thanks and if you notice others "mistakes", don't hesitate ! It's just like learning a speaking language, if you always say the same mistakes and people don't correct you, then you think it's the good way to say it... About the problem of concat to get the xml file name : I must display the name of the ME to the user, it shall not be a .xml. I could use <xsl:value-of select = "substring-before(ME/@id,'.xml')"/> to just display the name of the ME if i change id to XXXX.xml The problem is that the whole project is already done with <ME id="0041"> without .xml. It's right i could add .xml everywhere with a simple script... I'll think about it when i find the time. Do you think it will bring a lot ? will it go faster ? There's one thing I don't really understood : "But unfortunately using concat produces a string which stops document() automatically taking the union of all the documents in the node set." I don't see the link between concat id + ".xml" and the <xsl:value-of select="document($theFileName)..."/> $theFileName is not a node set, no ? XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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