Subject: Re: [xsl] From one xml put the data into 3 columns. Please help me From: Jeni Tennison <jeni@xxxxxxxxxxxxxxxx> Date: Mon, 8 Mar 2004 09:55:37 +0000 |
Hi Dionisio, > y have the bellow xml file and i want to put the data, the > paginas_titulo node in 3 columns: [snip] > if there are 5 nodes (paginas_titulo nodes) apears one row with 3 > columns with data and other row with 2 columns with data and the > other without data. The first task is to select one sn_masterinformacion element to represent each row, so that you generate the correct number of rows. The first sn_masterinformacion elements in each row are numbered 1, 4, 7 etc. You can select them by looking at the remainder after dividing by 3, using: sn_masterinformacion[position() mod 3 = 1] These sn_masterinformacion elements give the content for the first cell in each row. The next two sn_masterinformacion elements give the content for the following cells, if there are any. Since you just want the <td> to be empty in this case, the easiest thing is to create the cells and use the content from the next two following sibling sn_masterinformacion elements in them. Something like: <xsl:for-each select="sn_masterinformacion[position() mod 3 = 1]"> <tr> <td><xsl:apply-templates select="." /></td> <td> <xsl:apply-templates select="following-sibling::sn_masterinformacion[1]" /> </td> <td> <xsl:apply-templates select="following-sibling::sn_masterinformacion[2]" /> </td> </tr> </xsl:for-each> with a template for the sn_masterinformacion element just giving the value of the appropriate paginas_titulo element it contains: <xsl:template match="sn_masterinformacion"> <xsl:value-of select="paginas/sn_paginas/paginas_titulo" /> </xsl:template> Cheers, Jeni --- Jeni Tennison http://www.jenitennison.com/ XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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