Subject: Re: [xsl] XPath to get value of xmlns attribute From: "Emmanuil Batsis (Manos)" <mbatsis@xxxxxxxxxxx> Date: Tue, 09 Mar 2004 15:38:27 +0200 |
Hi, Say I have an xml document beginning as follows: <!--extract for example--> <?xml version="1.0" encoding="utf-8"?> <feed version="0.2" xmlns="http://purl.org/atom/ns#" xmlns:tt="http://www.tt.org/ns#"> <!--end of extract-->
I want to make a list of all atttributes (including namespace declaration ones). However, both of the templates below fail to pick up the xmlns and xmlns:tt attributes: <xsl:template match='@*'> <xsl:value-of select="name()"/> ='<xsl:value-of select="."/>' </xsl:template>
and
<xsl:template match="@*[starts-with(name(.),'xmlns')]" > <xsl:value-of select="name()"/> ='<xsl:value-of select="."/>' </xsl:template>
Can someone please tell me how I can get these values?
Thanks, Munna
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