Subject: [xsl] Cannot get numeric value - what am I doing wrong? From: "Kyle Partridge" <kpartridge@xxxxxxxxxxxx> Date: Thu, 18 Mar 2004 16:44:56 -0500 |
Hi all, This is probably an easy question for you to answer, but I'm stumped. I've got this variable I'm trying to assign a NUMERIC value to: <xsl:variable name="top-remove"> <xsl:choose> <xsl:when test="string($prior-break-regions)"> <xsl:call-template name="add-up"> <xsl:with-param name="set-one" select="$prior-break-regions/@top"/> <xsl:with-param name="set-two" select="$prior-break-regions/@height"/> </xsl:call-template> </xsl:when> <xsl:otherwise><xsl:value-of select="number('0')"/></xsl:otherwise> </xsl:choose> </xsl:variable> It calls a template, "add-up" which takes two sets of number node-sets and adds them all together. This, too, is supposed to return a NUMERIC value: <xsl:template name="add-up"> <xsl:param name="set-one"/> <xsl:param name="set-two"/> <xsl:param name="index" select="1"/> <xsl:param name="total" select="0"/> <xsl:choose> <xsl:when test="$index > count($set-one) or $index > count($set-two)"> <xsl:value-of select="number($total)"/> </xsl:when> <xsl:otherwise> <xsl:call-template name="add-up"> <xsl:with-param name="set-one" select="$set-one"/> <xsl:with-param name="set-two" select="$set-two"/> <xsl:with-param name="total" select="$total + $set-one[$index] + $set-two[$index]"/> <xsl:with-param name="index" select="$index + 1"/> </xsl:call-template> </xsl:otherwise> </xsl:choose> </xsl:template> So...HOW COME I wind up with a Node-Fragment type assigned to my variable, when all is said and done??? I need the value to be a numeric value, so that when I test to see if it is boolean true or false, it will react properly. Thanks, KP XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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