Subject: RE: [xsl] Problem with msxsl:node-set From: "M. David Peterson" <m.david@xxxxxxxxxx> Date: Sat, 27 Mar 2004 18:08:02 -0700 |
Normally you would use position() = $begin but it looks like you figured out a nice shortcut. By the way... I haven't forgot about this mornings email. I've been tied up in crazy things all day but I am finally getting a chance to sit down and get this worked out for you. I pulled in yesterdays "Difficult Grouping/Matching problem" as well because the solutions require similar grouping to get the desired output and it doesn't look like you had any responses. Im going to plug away at it each time I have a chance throughout the evening (if you can't already tell this is going to become one my tutorials for my latest consulting project as it's a good one to bring in dynamically generated content coupled with grouping and new element creation all as one standalone XSL file (I say stand alone meaning no additionally dependencies on outside functionality beyond that of which is normal such as accessing external documents and saving transformed files to the desired location and document format. (which, by the way, knowing you are sitting on a .NET box this would be an excellent candidate to bring in a web service to your customer creation and management solution. Don't worry I'm not making a shameless plug to drum up consulting business but simply letting you know that this solution will be designed with web services in mind for whatever the future of your project might hold. I think this one will be even more fun that the one I did this morning... definitely some unique characteristics to this problem. Best of luck! <M:D/> -----Original Message----- From: Kenny Akridge [mailto:kenny@xxxxxxxxxxxxxxxxx] Sent: Saturday, March 27, 2004 5:29 PM To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx Subject: RE: [xsl] Problem with msxsl:node-set I think I just figured it out right after I submitted this. [number($begin)] seems to be working. -----Original Message----- From: Kenny Akridge [mailto:kenny@xxxxxxxxxxxxxxxxx] Sent: Saturday, March 27, 2004 7:25 PM To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx Subject: [xsl] Problem with msxsl:node-set I have this variable, whose internal workings aren't very important: <xsl:variable name="uniqueClassDates"> <xsl:for-each select="ArrayOfAttendance/Attendance/ClassDate[number(substring(.,1,4)) > 0001 and not(. = preceding::ClassDate)]"> <xsl:element name="date"> <xsl:value-of select="."/> </xsl:element> </xsl:for-each> </xsl:variable> Which holds this value: <date>2004-01-10T00:00:00.0000000-05:00</date> <date>2004-01-11T00:00:00.0000000-05:00</date> <date>2004-01-12T00:00:00.0000000-05:00</date> The problem occurs while I am running this comparison: <xsl:if test="msxsl:node-set($uniqueClassDates)/date[$begin] = ClassDate"> In this case, $begin will be 1, 2 or 3. However, if I pass ClassDate with any value that is contained in $uniqueClassDates, it always returns true. How can I limit the logic to only return true when the $begin position of date matches ClassDate? Here is entire template: <xsl:template name="indexAttendanceCells"> <xsl:param name="begin"/> <xsl:param name="end"/> <xsl:choose> <xsl:when test="$begin > $end"></xsl:when> <xsl:otherwise> <xsl:variable name="attended"> <xsl:if test="msxsl:node-set($uniqueClassDates)/date[$begin] = ClassDate"> <xsl:text>true</xsl:text> </xsl:if> </xsl:variable> <xsl:choose> <xsl:when test="$attended = 'true'"> <td> X </td> </xsl:when> <xsl:otherwise> <td>   </td> <xsl:call-template name="indexAttendanceCells"> <xsl:with-param name="begin" select="$begin + 1"/> <xsl:with-param name="end" select="$end"/> </xsl:call-template> </xsl:otherwise> </xsl:choose> </xsl:otherwise> </xsl:choose> </xsl:template>
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