RE: [xsl] How to specify document order location path for identical elements with different parents?

["Andreas L. Delmelle" <a_l.delmelle@xxxxxxxxxx>]

> -----Original Message-----
> From: Alan Stein [mailto:as@xxxxxxxxxxx]
>
> Thanks much for the help with my previous posting.
>
> I think I've better articulated my question in the following example:
>
> Given the following XML:
>
<snip />
>
>
> How do I perform the following queries?
>
> 1)  What is the number of reports which are coded with either an "a" or
> "b" where the last "a" or "b" code of the report (in document order) is
> an "a"?
>

Hi,

To break it down:

1) reports coded with either an 'a' or 'b':

<xsl:variable name="var-one"
              select="report[codelist/code[
                @type='a' or @type='b']]" />

2) ... where the last 'a' or 'b' code in doc order is 'a'

<xsl:variable name="var-two"
              select="$var-one[codelist/code/@type[last()]='a']" />

all-in-one?

<xsl:variable name="vcount" select="count(/*/report[codelist/code[
                              @type='a' or @type='b']/@type[last()]='a'])"
/>

yup, should do the trick.. untested though


Hope this helps!

Cheers,

Andreas