RE: [xsl] Dynamical work with child nodes

Subject: RE: [xsl] Dynamical work with child nodes
From: Roland Juergens <roland_juergens@xxxxxxxxxxxx>
Date: Tue, 6 Apr 2004 16:23:49 +0200
Yes ! Thanks a lot, this helps. Now I only need to know how to get the total
number of children,
like *[max], and how to get the name (not the content) of the current node I
have selected with *[3]

Roland

-----Original Message-----
From: G. Ken Holman [mailto:gkholman@xxxxxxxxxxxxxxxxxxxx]
Sent: Dienstag, 6. April 2004 16:17
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: RE: [xsl] Dynamical work with child nodes


At 2004-04-06 16:08 +0200, Roland Juergens wrote:
>and how can i access a subelement without using its name ?

The node test for an element of any name is "*", so to access the value of 
the third child and you don't care for the name of the children would be:

   select="*[3]"

This node test is often used to check if the immediately preceding or 
following element is of a particular type, first by finding the closest of 
any name and then checking to see if that one is of the type you are 
looking for, in this case "is my immediately preceding sibling a figure 
element?":

   test="preceding-sibling::*[1][self::figure]"

I hope this helps.

......................... Ken


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