RE: [xsl] Dynamical work with child nodes

["G. Ken Holman" <gkholman@xxxxxxxxxxxxxxxxxxxx>]

At 2004-04-06 16:23 +0200, Roland Juergens wrote:
> Yes ! Thanks a lot, this helps. Now I only need to know how to get the total
> number of children,

count(*) will return the count of the child elements of any name.

> like *[max],

"max"? *[max] will give you the children elements that have element 
children named "max".

> and how to get the name (not the content) of the current node I
> have selected with *[3]

name(*[3]) ... but this is only good for exposition, not for testing.

Again, look at my earlier email ... when testing for an element it is not 
namespace safe to use the name() function.  I remind my students that 
name() is only for exposition and not for element identity testing ... use 
the self:: axis instead.

To test for "am I a figure element" use:   test="self::figure"

I hope this helps.

................... Ken

> From: G. Ken Holman [mailto:gkholman@xxxxxxxxxxxxxxxxxxxx]
> Sent: Dienstag, 6. April 2004 16:17
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Subject: RE: [xsl] Dynamical work with child nodes
> ...
> This node test is often used to check if the immediately preceding or
> following element is of a particular type, first by finding the closest of
> any name and then checking to see if that one is of the type you are
> looking for, in this case "is my immediately preceding sibling a figure
> element?":
>
>    test="preceding-sibling::*[1][self::figure]"


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