Subject: RE: [xsl] XML to Table From: "Andreas L. Delmelle" <a_l.delmelle@xxxxxxxxxx> Date: Fri, 16 Apr 2004 20:12:57 +0200 |
> -----Original Message----- > From: Veronica Sanchez [mailto:vsguiseris@xxxxxxxxxxx] > Hi, > The question is that i have problems with the first step, the xsl is too > slow and i can't create the node that doesn't exist in the row and that I > want to visualize. > Try this: <xsl:stylesheet ..> <xsl:template match="/"> <xsl:copy> <xsl:apply-templates select="ROWSET/ROW" /> </xsl:copy> </xsl:template> <xsl:template match="ROW"> <xsl:apply-templates select="../../DETAIL"> <xsl:with-param name="prow" select="current()/@num"> </xsl:apply-templates> </xsl:template> <xsl:template match="DETAIL"> <xsl:param name="prow" select="0" /> <xsl:for-each select="COLUMN"> <xsl:element name="{current()/@name}"> <xsl:value-of select="/XML/ROWSET/ROW[$prow]/*[ name()=current()/@name]" /> </xsl:element> </xsl:for-each> </xsl:template> > I can change the structure of <DETAIL></DETAIL> if it would be necessary. Nope. I don't think that's necessary. The trick in the above is that when the xsl:value-of returns nothing, an empty node is created, so there is no need for the xsl:choose. > > If it's possible i would prefer the use of one only xml. can I do it? > > > Thanks to all. > > _________________________________________________________________ > Correos mas divertidos con fotos y textos incrembles en MSN 8. Pruibalo > gratis dos meses. http://join.msn.com/?pgmarket=es-es&XAPID=45&DI=1055
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