Subject: RE: [xsl] Problem with xsl:if From: "Kenny Akridge" <kenny@xxxxxxxxxxxxxxxxx> Date: Wed, 21 Apr 2004 12:09:30 -0400 |
You could do if not() or xsl:choose. But you may want to check your logic. -----Original Message----- From: Gerald Fingerlos [mailto:gerald@xxxxxxxxxxxx] Sent: Wednesday, April 21, 2004 12:05 PM To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx Subject: [xsl] Problem with xsl:if I have the following XML Document: <?xml version="1.0" encoding="UTF-8"?> <input> <add class-name="User"> <add-attr attr-name="jkuSLABS"> <value>90</value> </add-attr> <add-attr attr-name="jkuSLART"> <value>50</value> </add-attr> <add-attr attr-name="jkuPeHabd"> <value type="string">7777-33-11</value> </add-attr> </add> </input> What Id like to to is the get an output document which should contain the <add-attr attr-name="jkuPeHabd"> <value type="string">7777-33-11</value> </add-attr> only, if the jkuSLABS=90 AND jkuSLART=50. Otherwise the 3 lines should be omitted. I thought of the following, but I think I am misunderstanding something: <xsl:template match="node()|@*"> <xsl:copy> <xsl:apply-templates select="@*|node()"/> </xsl:copy> </xsl:template> <xsl:template match="*[@attr-name='jkuPeHabd']"> <xsl:variable name="slart" select="//*[@attr-name='jkuPeBeschSAP22SLART']//value"/> <xsl:variable name="slabs" select="//*[@attr-name='jkuPeBeschSAP22SLABS']//value"/> <xsl:if test="($slart!='50') or ($slabs!='90')"> </xsl:if> </xsl:template> As far as I can see the if never gets true, but still if it would be true, I would need some "else" operation. Maybe you can give me a hint how to solve this. Thank you in advance, Gerald
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