[xsl] Xpath of an attribute

Subject: [xsl] Xpath of an attribute
From: "Animesh Sharma" <asharma@xxxxxxxxxxxxxxxx>
Date: Tue, 27 Apr 2004 14:17:55 +0530
hi,

I want to remove a particular attribute of node. 
Is there way that I can write the template in one line something like:

<xsl:template match="//body/namespace/form/snip/csf/div/center/p[position()=1]/a[position()=1][@href]"/>

<xsl:template match="*|text()|@*">
<xsl:copy>
<xsl:apply-templates select="*|text()|@*"/>
</xsl:copy>
</xsl:template>

This removes the anchor element.. but I just want to remove the "href" attribute of element.

Regards,
Animesh

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