Subject: RE: [xsl] Using XPath to retrieve nodes by attribute. From: "Kenny Akridge" <kenny@xxxxxxxxxxxxxxxxx> Date: Thu, 29 Apr 2004 09:19:34 -0400 |
This will give you quickbrownfox. Let me know if I have misunderstood your question. <?xml version="1.0"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:template match="/xml"> <xsl:value-of select="CCC/DDD[@attrib='123'][1]"/> <xsl:value-of select="CCC/DDD[@attrib='456'][1]"/> <xsl:value-of select="CCC/DDD[@attrib='456'][2]"/> </xsl:template> </xsl:stylesheet> -----Original Message----- From: Manuel Reyes [mailto:Manuel.Reyes@xxxxxxxxx] Sent: Thursday, April 29, 2004 9:11 AM To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx Subject: [xsl] Using XPath to retrieve nodes by attribute. Hello all, I have the following XML document: <xml> <AAA>foo</AAA> <BBB>bar</BBB> <CCC> <DDD attrib="123">quick</DDD> <DDD attrib="456">brown</DDD> <DDD attrib="789">fox</DDD> <DDD attrib="123">jumped</DDD> <DDD attrib="456">lazy</DDD> <DDD attrib="789">dog</DDD> </CCC> </xml> If I run the following XPath query it returns the count of all nodes in CCC that have an attrib value of "123": xml/CCC/DDD[@attrib='123'] = 2 What I am trying to do now is retrieve a particular node based on the position in the CCC node and its attribute, something like this: xml/CCC/DDD[@attrib='123'][1] = quick xml/CCC/DDD[@attrib='456'][1] = brown xml/CCC/DDD[@attrib='456'][2] = lazy This is based on information I found here: http://www.w3schools.com/xpath/xpath_location.asp Unfortunately this does work, can anybody tell me where I am going wrong Thanks Manuel
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