RE: Re: [xsl] how to split one xml to multiple xml files

["Michael Kay" <mhk@xxxxxxxxx>]

> Rerun the xsl using saxon7.jar.  I got this error:
> D:\projects\epubs_xslt\src\gmemd\xml\cat\cat701>java -jar
> ..\..\..\..\..\lib\sax
> on7.jar cat701.xml ..\..\..\xsl\createCatToc.xsl
> Error at result-document on line 11 of
> file:/D:/projects/epubs_xslt/src/gmemd/xm
> l/cat/cat701/../../../xsl/createCatToc.xsl:
>   The system identifier of the principal output file is unknown
> Transformation failed: Run-time errors were reported
> 
> What does it mean? 

It means you haven't specified the -o option on the command line, or the
equivalent in the API. This is needed for resolving a relative URI in the
href attribute.

 I tried to create another variable to specify the
> directory like this:
> <xsl:variable name="dir" select="d:\results" />
> But I got the error stating   "XPath syntax error in {D:/results}:
>     QName cannot end with colon: {D:}
> Transformation failed: Failed to compile stylesheet. 1 error detected.
>

The value of the select attribute of xsl:variable is an XPath expression.
You probably meant to write
<xsl:variable name="dir" select="'d:\results'" />

but that wouldn't do you much good either, because the href value must be a
URI, not a filename.

Michael Kay