Subject: Re: [xsl] Recursive apply-templates From: Mukul Gandhi <mukul_gandhi@xxxxxxxxx> Date: Wed, 5 May 2004 07:59:04 -0700 (PDT) |
Hi Sam, Following is an identity transform which outputs XML exactly same as the input XML. Regards, Mukul > How do I write a template match so that all the > output > XML looks exactly like the input XML. <?xml version="1.0" encoding="UTF-8"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/> <xsl:template match="/"> <xsl:copy-of select="@* | node()" /> </xsl:template> </xsl:stylesheet> > Thanks > Sam __________________________________ Do you Yahoo!? Win a $20,000 Career Makeover at Yahoo! HotJobs http://hotjobs.sweepstakes.yahoo.com/careermakeover
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