Subject: RE: [xsl]Transforming XML to XSL-FO by XSLT in java From: Arulraj <p_arulraj@xxxxxxxxx> Date: Thu, 6 May 2004 00:30:45 -0700 (PDT) |
--- Jarno.Elovirta@xxxxxxxxx wrote: > Xalan-J documentation has examples of this > <http://xml.apache.org/xalan-j/usagepatterns.html#basic>, > did you look at them? > > Cheers, > > Jarno - Rotersand: Electronic World Transmission > ([:SITD:] reconstruction) > Hi Jarno, I wrote the code by using procedure given in above site using java; Java code follows; import java.io.FileNotFoundException; import java.io.FileOutputStream; import java.io.IOException; import javax.xml.transform.Transformer; import javax.xml.transform.TransformerConfigurationException; import javax.xml.transform.TransformerException; import javax.xml.transform.TransformerFactory; import javax.xml.transform.stream.StreamResult; import javax.xml.transform.stream.StreamSource; public class xml2fo { public static void main(String[] args){ try{ TransformerFactory tFactory = TransformerFactory.newInstance(); Transformer transformer = tFactory.newTransformer(new StreamSource("Furniture.xsl")); transformer.transform(new StreamSource("Furniture.xml"), new StreamResult(new FileOutputStream("Furniture.fo"))); } catch(Exception e){ } } } But it shows the error like this; C:\xalan\samples\SimpleTransform>java xml2fo [Error] Furniture.xsl:5:391: Document root element "xsl:stylesheet", must mat DOCTYPE root "xml". [Error] Furniture.xsl:5:391: Element type "xsl:stylesheet" must be declared. [Error] Furniture.xsl:6:30: Element type "xsl:output" must be declared. [Error] Furniture.xsl:7:35: Element type "xsl:variable" must be declared. I am not able to find whether it is XSLT or Java coding.. Regards Arul __________________________________ Do you Yahoo!? Win a $20,000 Career Makeover at Yahoo! HotJobs http://hotjobs.sweepstakes.yahoo.com/careermakeover
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