Re: [xsl] count the number of descending nodes

["G. Ken Holman" <gkholman@xxxxxxxxxxxxxxxxxxxx>]

At 2004-05-06 15:33 +0200, Dionisio Ruiz de Zarate wrote:
> hello
> i have one xml as this:
> ...
> i want to see if above of the no node there is one or more nodes with the
> name my.
> i make this:
> <xsl:for-each select="/root/no">
> <xsl:choose>
> <xsl:when test="'count(my) =1'">ok</xsl:when>

You shouldn't have put the test into single quotes ... a working example is 
below.

I hope this helps.

................ Ken

T:\>type dionisio.xml
<root>
 <no>
  <my>w</my>
  <my>e</my>
 </no>
 <no>
  <my>p</my>
 </no>
</root>

T:\>type dionisio.xsl
<?xml version="1.0" encoding="iso-8859-1"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
                version="1.0">

<xsl:output indent="yes"/>
<xsl:output method="text"/>

<xsl:template match="/">
  <xsl:for-each select="/root/no">
    <xsl:choose>
      <xsl:when test="count(my)=1">ok</xsl:when>
      <xsl:otherwise>no</xsl:otherwise>
    </xsl:choose>
    <xsl:text>
</xsl:text>
  </xsl:for-each>
</xsl:template>

</xsl:stylesheet>
T:\>saxon dionisio.xml dionisio.xsl
no
ok

T:\>

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