Subject: RE: [xsl] Changing Attribute Value in all the ChildNodes at any level down the current node. From: "Andreas L. Delmelle" <a_l.delmelle@xxxxxxxxxx> Date: Thu, 27 May 2004 18:09:34 +0200 |
> -----Original Message----- > From: Animesh Sharma [mailto:asharma@xxxxxxxxxxxxxxxx] > Hi, > I have to remove a particular attribute (in following example it > is "href") from all the ChildNodes of the particular node. > > I tried to write template something as follows: > > <xsl:template > match="//body/namespace/form/snip/csf/td[position()=1]/table[posit > ion()=2]"> > <xsl:apply-templates select="@*"/> > <xsl:attribute name="href"/> AFAIK, xsl:attribute is not a self-closing element, so if you really want to create an empty href attribute, at least there should be <xsl:attribute name="href"></xsl:attribute> Although, I'm not sure whether this will work... (haven't needed or tested anything like it) If you just want to omit the href attribute from being output, you have two options: For both: remove the 'empty' xsl:attribute element you specified above. It serves no purpose. 1. replace <xsl:apply-templates select="@*" /> by <xsl:apply-templates select="@*[not(name()='href')]" /> 2. keep the current form of the apply-templates instruction, and define a null template matching @href, like <xsl:template match="@href" /> Hope this helps! Greetz, Andreas
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