Subject: RE: [xsl] xsl-list@lists.mulberrytech.com From: "Michael Kay" <mhk@xxxxxxxxx> Date: Sun, 6 Jun 2004 13:18:38 +0100 |
count((C|D)[1]/preceding-sibling::*) + 1 alternatively: <xsl:for-each select="(C|D)[1]"> <xsl:number count="*"/> </xsl:for-each> Michael Kay > -----Original Message----- > From: Chen Yi [mailto:chen_yi36@xxxxxxxxxxx] > Sent: 06 June 2004 08:09 > To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx > Subject: [xsl] xsl-list@xxxxxxxxxxxxxxxxxxxxxx > > ALL, > > For example, > > <element> > <A/> > <B/> > <A/> > <C/> > <C/> > <D/> > </element> > > I want to get the position first element whoes name is not A > and B, but C & > D. So it's 4 for this tree segment. > How can I write the xslt to figure out this ? > > Thanks, > Chen Yi > > _________________________________________________________________ > 免费下载 MSN Explorer: http://explorer.msn.com/lccn/ > > > --+------------------------------------------------------------------ > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list > To unsubscribe, go to: http://lists.mulberrytech.com/xsl-list/ > or e-mail: <mailto:xsl-list-unsubscribe@xxxxxxxxxxxxxxxxxxxxxx> > --+-- > >
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