Re: [xsl] i18n problem while displaying using stylesheet

Subject: Re: [xsl] i18n problem while displaying using stylesheet
From: Josh Canfield <joshcanfield@xxxxxxxxx>
Date: Fri, 25 Jun 2004 01:27:58 -0700
Hmm.. you probably need to provide a simple stylesheet that
demonstrates your problem.

Here is a sample I made up that works as I would expect, but I don't
know what your requirement is. The Japanese characters are output as
character references, but your browser should display them correctly.
(or what I suppose is correctly since I don't read Japanese...)

<?xml version="1.0" encoding="UTF-8"?>
 <xsl:stylesheet version="1.0" 
    xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
  <xsl:output method="html" encoding="UTF-8" indent="yes"/>

  <xsl:template match="/x">    
  <html><body>
    <xsl:apply-templates/>
    </body></html>
  </xsl:template>

  <xsl:template match="country">
    <b><xsl:value-of select="@name"/></b><br/>
  </xsl:template>

</xsl:stylesheet>
On Fri, 25 Jun 2004 00:53:31 -0700 (PDT), Ranjan K. Baisak
<ranjanbaisak@xxxxxxxxx> wrote:
> 
> Hello List,
>          My xml contains following elements with
> japanese characters.
> <country
> name="&#20837;&#21147;&#26989;&#21209;&#24037;&#25968;&#12398;&#21066;&#38500;"
> nameindex="1" />
> <country
> name="&#20837;&#21147;&#26989;&#24037;&#25968;&#12398;&#21066;&#38500;"
> nameindex="2" />
> I need to display japanese charachers as it is. My
> stylesheet displays acsii characters not japanese
> characters when it converts xml to html. Any
> suggestion regarding what are steps I need to take
> care to to show the content of "name" attribute as it
> is in html format.
> 
> regards,
> Ranjan
> 
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