Subject: Re: [xsl] Positional predicates in pattern matching From: David Carlisle <davidc@xxxxxxxxx> Date: Fri, 2 Jul 2004 16:44:32 +0100 |
your modes one and two are identical as the only difference is [true()] but a filter of [true()] never does anything. so to see why you get P2P3 $foo contains the second and third b child nodes of a so you apply templates to those two nodes. match patterns are always evaluated against the source document not against the node set used in the selection (you can't really use axis notation to navigate around a node set) so match="b[1]" matches any b that is the first b child of its parent match="b[2]" matches any b that is the second b child of its parent match="b[3]" matches any b that is the third b child of its parent so when you apply templates to the $foo wiich is the second and third b nodes the second and third templates fire and you get P1 from teh first and P2 from the second. then you do mode two which is identical except it writes out R2R3 david -- The LaTeX Companion http://www.awprofessional.com/bookstore/product.asp?isbn=0201362996 http://www.amazon.co.uk/exec/obidos/tg/detail/-/0201362996/202-7257897-0619804 ________________________________________________________________________ This e-mail has been scanned for all viruses by Star Internet. The service is powered by MessageLabs. For more information on a proactive anti-virus service working around the clock, around the globe, visit: http://www.star.net.uk ________________________________________________________________________
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