<-prev [Thread] next-> <-prev [Date] next->
Month Index | List Home

Re: [xsl] finding position in list of siblings

Subject: Re: [xsl] finding position in list of siblings
From: "John C Cartwright" <John.C.Cartwright@xxxxxxxx>
Date: Fri, 09 Jul 2004 13:29:36 -0600
works perfectly! Thanks for the prompt response.

-- john


cknell@xxxxxxxxxx wrote:
Try this template:

<xsl:template match="BROTHER">
   <xsl:value-of select="count(preceding-sibling::*[name()='BROTHER')" />
</xsl:template>



--
=====================================================
John Cartwright
Associate Scientist
Geospatial Data Services Group
CIRES, National Geophysical Data Center/NOAA
(303) 497-6284
John.C.Cartwright@xxxxxxxx
=====================================================

Current Thread
<- PreviousIndexNext ->
RE: [xsl] finding position in list , cknell Thread RE: Re: [xsl] finding position in l, cknell
RE: [xsl] finding position in list , cknell Date Re: [xsl] finding position in list , Wendell Piez
Month