Subject: Re: [xsl] finding position in list of siblings From: David Carlisle <davidc@xxxxxxxxx> Date: Sat, 10 Jul 2004 17:13:48 +0100 |
since you used <xsl:apply-templates select="/FAMILY/BROTHER" /> you can just use position() David ________________________________________________________________________ This e-mail has been scanned for all viruses by Star Internet. The service is powered by MessageLabs. For more information on a proactive anti-virus service working around the clock, around the globe, visit: http://www.star.net.uk ________________________________________________________________________
Current Thread |
---|
|
<- Previous | Index | Next -> |
---|---|---|
Re: [xsl] finding position in list , Wendell Piez | Thread | RE: [xsl] finding position in list , cknell |
Re: [xsl] Muenchian grouping: help , Mukul Gandhi | Date | [xsl] xpath dynamic selection, Wim Lemkens |
Month |