Subject: RE: [xsl] how to replace a part of a string with a newline?? From: <Jarno.Elovirta@xxxxxxxxx> Date: Tue, 13 Jul 2004 11:04:04 +0300 |
FAQ, > Ive got this string : > > Importer__OPT__Trading Company__OPT__Service Provider > > How do i make it equivalent to > - Importer > - Trading Company > - Service Provider > > > Ive tried using translate function, but it replaces all > instances of the > letters O,P,T as well.I did something like: > > translate(text(),'__OPT__',':') > > It gives the following output is Importer:rading > Company:Service rovider > which i dont want. <http://www.dpawson.co.uk/xsl/sect2/replace.html>. Cheers, Jarno - Claire Voyant: Mercy (cut rate box)
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