Subject: Re: [xsl] position() in sequences in XSLT 2.0 From: David Carlisle <davidc@xxxxxxxxx> Date: Thu, 15 Jul 2004 10:29:02 +0100 |
with saxon 8 with your original code I get a java stack overflow. Which is probably the correct thing (Although I suppose saxon could catch this and give a more xslt oriented error) the problem is that your $empty variable contains a tree with a document node containing an empty element so when you apply templates to three copies of it you apply templates to three / nodes which match your template for / and bang you loop ad infinitum. Change return $empty to return $empty/* so your sequence just has the elements or add as ="element()" to the xsl:variable declaration to suprress the implicit document node (don't do both of these) then: $ saxon8 s8.xml s8.xsl <?xml version="1.0" encoding="UTF-8"?> entry 1 of 6<br/> entry 2 of 6<br/> entry 3 of 6<br/> entry 4 of 6<br/> entry 5 of 6<br/> entry 6 of 6<br/> David ________________________________________________________________________ This e-mail has been scanned for all viruses by Star Internet. The service is powered by MessageLabs. For more information on a proactive anti-virus service working around the clock, around the globe, visit: http://www.star.net.uk ________________________________________________________________________
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