Subject: [xsl] Recursive attribute values From: "Kenny Bogoe (BogoeMD)" <kenny@xxxxxxxxx> Date: Fri, 16 Jul 2004 16:47:17 +0200 |
Hi, I am using this recursive template to generate N elements on the fly and it works perfect, but I also need to generate dynamic values for attribute "t" based on the variable $top. I have been experimenting a lot, but the result is always the same attribute value for all generated elements. As you can see in my output sample below the "t" value is changing every $top. Anyone know how to do this? <xsl:attribute-set name="td"> <xsl:attribute name="w">1</xsl:attribute> <xsl:attribute name="h">1</xsl:attribute> </xsl:attribute-set> <xsl:variable name="top">3</xsl:variable> <xsl:template name="td"> <xsl:param name="x"/> <xsl:param name="y"/> <xsl:element name="td" use-attribute-sets="td"> <xsl:attribute name="l"><xsl:value-of select="$y"/></xsl:attribute> <xsl:attribute name="t"><!--VALUES IS MISSING HERE--></xsl:attribute> </xsl:element> <xsl:if test="$x > 1"> <xsl:call-template name="td"> <xsl:with-param name="x" select="$x - 1"/> <xsl:with-param name="y" select="$y + 1"/> </xsl:call-template> </xsl:if> </xsl:template> This output I need ($top is determine the repetition of "t"): <td w="1" h="1" l="0" t="0"/> <td w="1" h="1" l="0" t="0"/> <td w="1" h="1" l="0" t="0"/> <td w="1" h="1" l="0" t="1"/> <td w="1" h="1" l="0" t="1"/> <td w="1" h="1" l="0" t="1"/> <td w="1" h="1" l="0" t="2"/> <td w="1" h="1" l="0" t="2"/> <td w="1" h="1" l="0" t="2"/> Etc. Thanks in advance Kenny Bogoe
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