Subject: Re: [xsl] node's full content + some modifications in that From: "Földényi Tamás" <ftomi@xxxxxxx> Date: Wed, 21 Jul 2004 18:59:26 +0200 |
Hello Mukul, Thanks for help! Can you help me in the case when the <tab/> is not the first child of <artist>? for example: <?xml version="1.0" encoding="ISO-8859-1"?> <?xml-stylesheet type="text/xsl" href="cdcatalog.xsl"?> <catalog> <cd> <artist><b>Eros <tab/> </b> <i>Rama<strike>z<tab/>z</strike>otti</i></artist> </cd> </catalog> The other problem that I don't want to predefine what can be used beside <b>. I could write match="artist/node()" instead of match="b". But the bigger problem is the first, that's minor. Thanks, Thomas ----- Original Message ----- > Hi Thomas, > This might help - > > <?xml version="1.0" encoding="ISO-8859-1"?> > <xsl:stylesheet version="1.0" > xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> > > <xsl:template match="/"> > <html> > <body> > <table> > <xsl:for-each select="catalog/cd"> > <tr> > <td> > <xsl:apply-templates select="artist"/> > </td> > </tr> > </xsl:for-each> > </table> > </body> > </html> > </xsl:template> > > <xsl:template match="artist"> > <xsl:apply-templates /> > </xsl:template> > > <xsl:template match="tab"> > <xsl:text> </xsl:text> > </xsl:template> > > <xsl:template match="b"> > <xsl:copy-of select="." /> > </xsl:template> > > </xsl:stylesheet>
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