Subject: [xsl] using exsl:node-set() From: "Markus Hanel" <markus.hanel@xxxxxx> Date: Mon, 26 Jul 2004 11:58:11 +0200 (MEST) |
hallo, I make something wrong! I want to use the exsl:node-set() function but at www.exsl.org there is no download of the exsl.node-set.xsl stylesheet. But in the main download there are two stylesheets: exsl.node-set.1.xsl and exsl.node-set.2.xsl, but this not works. markus <?xml version="1.0" encoding="iso-8859-1"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:exsl="http://exslt.org/common" extension-element-prefixes="exsl"> <xsl:import href="exsl.node-set.1.xsl" /> <xsl:import href="exsl.node-set.2.xsl" /> <xsl:template match="/"> <html> <head><title></title></head> <body> <xsl:apply-templates select="./table" /> </body> </html> </xsl:template> <xsl:template match="table"> <xsl:variable name="sorted-rows-rtf"> <xsl:for-each select="./row"> <xsl:sort select="sum(./cell/@points)" data-type="number" order="descending" /> <xsl:copy-of select="." /> </xsl:for-each> </xsl:variable> <xsl:variable name="sorted-rows" select="exsl:node-set($sorted-rows-rtf)/row" /> <xsl:value-of select="sum($sorted-rows[position() <= 4]/cell/@points)" /> </xsl:template> </xsl:stylesheet>
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