Re: [xsl] can you select name() of attributes?

Subject: Re: [xsl] can you select name() of attributes?
From: "Ragulf Pickaxe" <jawxml@xxxxxxxxxxx>
Date: Tue, 27 Jul 2004 11:01:16 +0000
Hi again David (and others),

The input and some of my problem should be in my earlier post "Matching attributes in two documents", but I have tried rewriting it a little to match this particular problem.

If some or all of this is not understandable, please tell me, and I will try to elaborate.


Doc1.xml <Input> <I q="input value" s="Invalid attribute">Input</I> </Input>

Doc2.xml
<A>
 <B q="default" r="default">Text1</B>
</A>

Desired output:
<Output q="input value" r="default">Some text in the output element</Output>

Output that I get:
<Output q="default" r="default">Some text in the output element</Output>

If the attribute exists in both Doc1 and Doc2, then I want the value of Doc1 (input value). If it exists only in Doc1, then it should be ignored (invalid attribute), and if only in Doc2, then I want the value of Doc2 (default)

XSL snippets (for the non-desired output):
<!-- Global variables -->
<xsl:variable name="Doc1" select="document('Doc1.xml')/Input/I"/>
<xsl:variable name="Doc2" select="document('Doc2.xml')/A/B"/>


<!-- Template for processing --> <xsl:template name="MakeOutput"> <xsl:variable name="Attr1" select="$Doc1/@*"/> <xsl:variable name="Attr2" select="$Doc2/@*"/>

<Output>
<xsl:for-each select="$Attr2">
<xsl:variable name="Attr" select="."/>
<xsl:if test="not($Attr1)">
<xsl:attribute name="{name($Attr)}"><xsl:value-of select="$Attr"/></xsl:attribute>
</xsl:if>
<xsl:for-each select="$Attr1[name()=name($Attr)]">
<xsl:choose>
<xsl:when test="name()=name($Attr)">
<xsl:attribute name="{name(.)}"><xsl:value-of select="."/></xsl:attribute>
</xsl:when>
<xsl:otherwise>
<xsl:attribute name="{name($Attr)}"><xsl:value-of select="$Attr"/></xsl:attribute>
</xsl:otherwise>
</xsl:choose>
</xsl:for-each>
</xsl:for-each>
Some text in the output element
</Output>
</xsl:template>


Regards,
Ragulf Pickaxe :-)

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