Subject: Re: [xsl] How to make a loop ? From: "cking" <cking@xxxxxxxxxx> Date: Wed, 28 Jul 2004 13:05:24 +0200 |
Hi Alain, you can do something like this: <xsl:variable name="n-rows" select="5"/> <xsl:template match="/"> <html> <head>...</head> <body> <table> <tr> <xsl:call-template name="td-recursive"/> </tr> </table> </body> </html> </xsl:template> <xsl:template name="td-recursive"> <xsl:param name="index" select="1"/> <td> <xsl:value-of select="info[$index]"/> </td> <xsl:if test="$index < $n-rows"> <xsl:call-template name="td-recursive"> <xsl:with-param name="index" select="$index + 1"/> </xsl:call-template> </xsl:if> </xsl:template> HTH, Anton Triest <quote from="Alain ROY"> > Hi all, > > I want to make a table which may contain always the same number of rows (actually 5 but this can change later). > I want to fill this table with nodes values (let's say "info" for example). If there are less "info" nodes than the number of rows > I chose for my table, I want to complete it with empty rows. If there are more "info" nodes than the number of rows of my table, I > want to fill the table with only the n firsts info nodes values (n=number of rows of my table). > To fill my table I made a template for the rows. So I'd like to make a loop which will always call this template n times with a > parameter info[x] x=1..n > > What's the best way to do that ? > > Regards > AR </quote>
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