Re: [xsl] Need exactly 23 rows of output before next page

Subject: Re: [xsl] Need exactly 23 rows of output before next page
From: "J.Pietschmann" <j3322ptm@xxxxxxxx>
Date: Thu, 12 Aug 2004 21:55:10 +0200
Clay Leeds wrote:
I am re-creating a medical form which outputs exactly 23 rows per page (i.e., if there are 3 rows of data, 23 nodes are output; if there are 24 rows of data, 46 nodes are output, w page one having 23 rows of data, and page 2 having one row of data filled/22 rows empty, etc.).

Uhh, requirements straight out of hell... You can compute the number of rows necessary to make the total number a multiple of 26 using the mod operator, and fill the missing rows using the wendell-piez-method or a recursive template:

<xsl:for-each select="DETAILLINE">
<fo:table-row height=".8cm" border=".5pt solid {$varColor}"
border-collapse="collapse" line-height="22pt">
<fo:table-cell text-align="center" border-bottom=".5pt solid {$varColor}">
<xsl:value-of select="DOSFROM/MM"/>
<xsl:variable name="detail-count" select="count(DETAILLINE)"/>
<xsl:if test="($detail-count mod 23) != 0">
<xsl:for-each select="//node()[position() <
(24 - ($detail-count mod 23))]">
... add empty rows ...

There should be multiple alternative, possibly more elegant
and/or correct formulations of the solution. If performance
is bad, switch to a recursive template (the XSLT FAQ has it


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