Subject: RE: [xsl] how to sort by different attributes in a table From: "Michael Kay" <mhk@xxxxxxxxx> Date: Mon, 30 Aug 2004 22:05:44 +0100 |
This is a FAQ. Use <xsl:sort select="@*[local-name() = $Sort]"/> The reason your attempt doesn't work is that a sort key such as $Sort that doesn't depend on the context node will have the same value for each of the nodes in the node-set being sorted. The system can't guess that you want to treat the value of this variable, e.g. "HOSTNAME", as an XPath expression. Michael Kay > -----Original Message----- > From: Shen, Ching [mailto:Shenc@xxxxxxxx] > Sent: 30 August 2004 20:54 > To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx > Subject: [xsl] how to sort by different attributes in a table > > > I have a xml file which looks like > <Rows> > <Row> > <Columns A=3D"HOSTNAME" B=3D"IPADDRESS" C=3D"BRAND/MODEL" /> > </Row> > <Row> > <Columns A=3D"AA" B=3D"23" C=3D"ibm" /> > </Row> > ...... > </Rows> > > > I have all attributes list in a table as columns and I need a > xsl syntax = > which will allow me to sort by selected attribute, when they click = > attribute header,=20 > > i. e. when user click 2nd column header, all xml file will sorted by = > <xsl:sort select=3D"*/@B" /> > > The following syntax failed to work and I run out clue. Here header = > link set to Sort=3D{position()}=20 > > <xsl:apply-templates select=3D"*/*"> > <xsl:sort select=3D"*/@Columns[$Sort]" /> > </xsl:apply-templates> > > Does anybody have done this before and can help me out with > right syntax? > Your suggestions will be greatly appreciated > > > Thank you! > > Ching
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