Subject: Re: [xsl] Sorting and replacing content From: David Carlisle <davidc@xxxxxxxxx> Date: Wed, 1 Sep 2004 10:43:03 +0100 |
> I have this structure where the content of tags <A> to <E> have to determine > the order of tag-content <a> to <e>. The result needs to be as shown below. Tags and elements are not the same thing, the content of the start tag <A> is "A" the content of the end tag </A> is also "A" and 3 is not inside any tag at all (that's why it's known as element content: it's in an element but not in a tag). XSLT of course has no direct access to the tags at all they have been resolved by teh parser into an input node tree, That said, I think you want something like <xsl:variable name=u" select="ABCDEFGHIJKLMNOPQRSTUVWXYZ"/> <xsl:variable name=l" select="abcdefghijklmnopqrstuvwxyz"/> <xsl:for-each select="*[translate(name(),$u,'')='']"> <xsl:sort datatype="number" select="."/> <xsl:variable name="ll" select="translate(name(),$u,$l"/> <no><xsl:value-of select="/root/*[name()=$ll]"/></no> </xsl:for-each> David ________________________________________________________________________ This e-mail has been scanned for all viruses by Star Internet. The service is powered by MessageLabs. For more information on a proactive anti-virus service working around the clock, around the globe, visit: http://www.star.net.uk ________________________________________________________________________
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