[xsl] Classic many-to-many sorting

[Frans Englich <frans.englich@xxxxxxxxx>]

Hello all,

I have a document containing:

<object name="a" property="foo"/>
<object name="b" property="bar"/>
<object name="c"  property="foo"/>
<object name="d" property="bar"/>
<object name="e" property="bar"/>
[...]

The name is unique and there are many different kinds of values of property, 
some of them duplicates or more, like in the example.

What I want to do is a classic sorting: List all objects that have the same 
property value. For example:

Object "a" and "c", have their property attribute set to "foo".
Object "b","d" and "e", have their property attribute set to "bar".
[etc.]

With a traditional programming language this would have been easy, but what is 
the best and Right Way to do it in XSLT? Or should I resort to for-each and 
if's?

I can change the generation of the source document, if that is of interest.


Thanks in advance,


			Frans