RE: [xsl] xsl:if

Subject: RE: [xsl] xsl:if
From: <KS.Bhaskar@xxxxxxxxxxxxxxxxxx>
Date: Mon, 27 Sep 2004 13:16:59 +0530
Hi,

You just try with this.

<xsl:variable name="currencyTmp" select="select_value_in_some_cell"/>
<xsl:if test="0 = string-length($currencyTmp)">
	<xsl:variable name="currencyTmp"
select="select_value_in_some_other_cell"/>
</xsl:if>


Regards,
Bhaskar


-----Original Message-----
From: Andreas Andersson [mailto:andreas@xxxxxxxxxxxxxx]
Sent: Monday, September 27, 2004 1:08 PM
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: [xsl] xsl:if

Hi!

I'm trying to test if a variable is the empty string or not, I can't
find out how to do it with xsl:if. Here is what I have:

<xsl:variable name="currencyTmp" select="select_value_in_some_cell"/>
<xsl:if test="$currencyTmp=''">
	<xsl:variable name="currencyTmp"
select="select_value_in_some_other_cell"/>
</xsl:if>

I know that my selects work, but the ifs doesn't?

Anyone know what I'm doing wrong?

Thanks.

--
Andreas Andersson
IT Dept.
Travelstart Nordic
andreas@xxxxxxxxxxxxxx
http://www.travelstart.se





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