Subject: [xsl] What's the correct way to output an element to the result tree From: Peter Lerche <peter@xxxxxxxxxxxxxx> Date: Wed, 29 Sep 2004 14:20:33 +0200 |
Hi, I was looking through this mailing-list trying to find an answer. However I found a question (posted in 2001) which addressed my problem but no answer. Therefore I am quoting the original question hoping somebody has the answer. -QUOTE- What's the correct way to output an element to the result tree from within the code of an extension element (or function)? As a dummy example, let's say I want to write a Javascript extension element (using the Xalan-Java processor) to output a <p> tag, then process the child elements of the context node, then output a </p> tag. The code I've got at the moment is <?xml version="1.0"?> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"; xmlns:lxslt="http://xml.apache.org/xslt"; xmlns:my="MyNamespace" extension-element-prefixes="my" version="1.0"> <lxslt:component prefix="my" elements="para"> <lxslt:script lang="javascript"> <![CDATA[ function para(xslContext,thisElement) { xslContext.outputToResultTree(xslContext.getStylesheet(),"<p>"); xslTrans = xslContext.getTransformer(); xslTrans.executeChildTemplates(thisElement, xslContext.getContextNode(), xslContext.getMode(), true ); xslContext.outputToResultTree(xslContext.getStylesheet(),"</p>"); return null; } ]]> </lxslt:script> </lxslt:component> <xsl:template match="/"> <my:para> This is a paragraph. </my:para> </xsl:template> </xsl:stylesheet> Of course, this isn't right. I don't want to output the text strings '<p>' and '</p>'; I want to output an element node <p>. -UNQUOTE- -- Med venlig hilsen / Yours sincerely Peter http://easyspeedy.com _______________________________________ European Dedicated Server Hosting Extremely low prices, secure, and reliable Linux and BSD distributions only _______________________________________
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