Re: [xsl] Output a default value for an empty node

Subject: Re: [xsl] Output a default value for an empty node
From: Aaron Johnson <Aaron2.Johnson@xxxxxxxxx>
Date: Wed, 06 Oct 2004 14:31:13 +0100
Thanks for your reply David....

I stuck with my initial foray into if/when etc...and came up with this:

<xsl:choose>
<xsl:when test="string-length(member_name)=0">Unassigned</xsl:when>
<xsl:otherwise>
<xsl:value-of select="member_name"/>
</xsl:otherwise>
</xsl:choose>

AJ
......................................................................

Aaron Johnson
GUI / XSLT development
Academic Technologies Group [ATG]
University of the West of England

ext: 81051
t: 0117 3281051 
www: http://atg.uwe.ac.uk/aaron
e: aaron2.johnson@xxxxxxxxx
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> From: David Carlisle <davidc@xxxxxxxxx>
> Reply-To: <xsl-list@xxxxxxxxxxxxxxxxxxxxxx>
> Date: Wed, 06 Oct 2004 12:07:27 +0100
> To: <xsl-list@xxxxxxxxxxxxxxxxxxxxxx>
> Subject: Re: [xsl] Output a default value for an empty node
> 
> 
> <xsl:template match="foo">
>  <xsl:copy-of select="."/>
> </xsl:template>
>  
> <xsl:template match="foo[not(text()]">
>  <foo>hello mum</foo>
> </xsl:template>
>  
> will convert
> 
> <foo>zzz</foo> to <foo>zzz</foo>
> and
> <foo/>         to <foo>hello mum</foo>
> 
> David
> 
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