Subject: [xsl] how select all siblings? From: "Hardy Merrill" <HMerrill@xxxxxxxxxxxxxxxx> Date: Tue, 12 Oct 2004 14:42:17 -0400 |
Here's a snippet from an XSL style sheet: <xsl:template name="display_section"> <xsl:param name="section_legislators"/> <tr><td colspan="4">Count section_legislators:<xsl:value-of select="count($section_legislators)"/></td></tr> <xsl:variable name="sorted_legislators"> <xsl:for-each select="$section_legislators"> <xsl:sort select="district_type" /> <xsl:sort select="district_no" data-type="number" /> <xsl:sort select="legislator_active_date" data-type="number" order="descending" /> <xsl:copy-of select="."/> </xsl:for-each> </xsl:variable> <tr><td colspan="4">Count sorted_legislators: <xsl:value-of select="count(msxsl:node-set($sorted_legislators))"/></td></tr> ------------------------------------------------------------------------------- Param "section_legislators" is a node-list consisting of many "legislator" nodes - each legislator node has several child nodes like "full_name", "district_type", etc. I put in the <tr> tag displaying Count section_legislators to ensure that "section_legislators" is really a node list. That <tr> displays a row saying that there are 243 for a count of section_legislators. But, the <tr> displaying the count of sorted_legislators shows only 1. I'm sure my for-each select is incorrect for variable "sorted_legislators". I want *all* legislator nodes in "section_legislators" to be in "sorted_legislators" - just sorted. What should my "select" in the for-each be for "sorted_legislators"? Thanks. Hardy Merrill
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