Re: [xsl] XPath Error

[Geert Josten <Geert.Josten@xxxxxxxxxxx>]

Hi,

> <xsl:variable name="myInfo">
>         <xsl:copy-of select="/page/myinfo" />
> </xsl:variable>

If possible prefer the following:

  <xsl:variable name="myInfo" select="/page/myinfo" />

That way the myInfo variable contains a node set and not a document fragment. The upper version will 
give an error when evaluating $myInfo/myinfo/@id. This is a limitation of XSLT 1. In XSLT 2 the 
document fragment data type does not exist.

If it is not possible to use the select attribute on xsl:variable (perhaps because you want to call 
a separate template that gives a node set), you could resort to the node-set function, which is 
supported by most implementations of XSLT 1.

You could then use something like:

  <xsl:variable name="id" select="exsl:node-set($myInfo)/myinfo/@id" />

(Note: see exslt.org for explanation on the extension functions, their use and availability in 
implementations)

Grtz,
Geert

--
Geert.Josten@xxxxxxxxxxx
IT-consultant at Daidalos BV, Zoetermeer (NL)

http://www.daidalos.nl/
tel:+31-(0)79-3316961
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