Subject: AW: [xsl] Variables and command line params From: "Huditsch Roman" <Roman.Huditsch@xxxxxxxxxxxxx> Date: Tue, 9 Nov 2004 12:59:32 +0100 |
Hi Kevin, Have you declared your second variable "filename", too? <xslvariable name="filename"/> Wbr, Roman > -----Urspr|ngliche Nachricht----- > Von: Kevin Bird [mailto:kevin.bird@xxxxxxxxxxxxxxxxxxxxxxx] > Gesendet: Dienstag, 9. November 2004 12:55 > An: xsl-list@xxxxxxxxxxxxxxxxxxxxxx > Betreff: [xsl] Variables and command line params > > Hi > > I want to pass a second filename as a parameter from the command line. > > > The below variable declaration works in my stylesheet when the filename > is hardcoded. > > <xsl:variable name="list2" select="doc('filename.xml')//supp"/> > > But when I change to... > > <xsl:variable name="list2" select="doc($filename)//supp"/> > > ...and add > > filename="filename.xml" > > to the command line option, I get an error - $filename has not been > declared. > > Can someone please point out what I am doing wrong. > > Thanks. > > -- > Kevin ********************************************************************** This email and any files transmitted with it are confidential and intended solely for the use of the individual or entity to whom they are addressed. If you have received this email in error please notify the system manager. This footnote also confirms that this email message has been swept by MIMEsweeper for the presence of computer viruses. www.mimesweeper.com **********************************************************************
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