AW: [xsl] Variables and command line params

Subject: AW: [xsl] Variables and command line params
From: "Huditsch Roman" <Roman.Huditsch@xxxxxxxxxxxxx>
Date: Tue, 9 Nov 2004 12:59:32 +0100
Hi Kevin,

Have you declared your second variable "filename", too?

<xslvariable name="filename"/>

Wbr,
Roman

> -----Urspr|ngliche Nachricht-----
> Von: Kevin Bird [mailto:kevin.bird@xxxxxxxxxxxxxxxxxxxxxxx]
> Gesendet: Dienstag, 9. November 2004 12:55
> An: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Betreff: [xsl] Variables and command line params
>
> Hi
>
> I want to pass a second filename as a parameter from the command line.
>
>
> The below variable declaration works in my stylesheet when the filename
> is hardcoded.
>
> <xsl:variable name="list2" select="doc('filename.xml')//supp"/>
>
> But when I change to...
>
> <xsl:variable name="list2" select="doc($filename)//supp"/>
>
> ...and add
>
> 		filename="filename.xml"
>
> to the command line option, I get an error - $filename has not been
> declared.
>
> Can someone please point out what I am doing wrong.
>
> Thanks.
>
> --
> Kevin



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