Subject: Re: [xsl] Variables and command line params From: xptm@xxxxxxx Date: Tue, 9 Nov 2004 12:02:36 +0000 |
How about <xsl:variable name="list2" select="doc('$filename')//supp"/> Citando Kevin Bird <kevin.bird@xxxxxxxxxxxxxxxxxxxxxxx>: > Hi > > I want to pass a second filename as a parameter from the command line. > > > The below variable declaration works in my stylesheet when the filename > is hardcoded. > > <xsl:variable name="list2" select="doc('filename.xml')//supp"/> > > But when I change to... > > <xsl:variable name="list2" select="doc($filename)//supp"/> > > ...and add > > filename="filename.xml" > > to the command line option, I get an error - $filename has not been > declared. > > Can someone please point out what I am doing wrong. > > Thanks. > > -- > Kevin > > Ganha Cbmaras de Filmar, Televisues e outros fantasticos primios Samsung com o SAPO! Clica em http://dc.sapo.pt/sfc
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