RE: [xsl] Problem passing node-set to params (RTF)

["Evan Lenz" <evan@xxxxxxxxxxxx>]

Hi Charlie,

It shouldn't matter whether you use a variable reference or expression,
provided that the variable was declared using the "select" attribute. The
only time RTFs are created is when you use <xsl:variable>, etc. with
*content* rather than the "select" attribute.

What XSLT processor are you using? And what is the undesired behavior? An
error message?

Evan

> I'm having trouble passing a node-set as a parameter. 
> I'm trying to reduce the size of my XSL so its more
> managable and easier to modify.  So I've taken a
> section of code that was repeated over my XSL and
> turned it into a template with parameters.  I'm trying
> to use call-template to pass in the parameters, but my
> srcNode and destNode parameters are turning into
> Result Tree Fragments.  After reading the FAQ it said
> that assigning existing variables to parameters turns
> them into RTF.  But, when I tried replacing them with 
> expressions rather than $var it still ended up a RTF. 
> What do I have to do to use node-sets?
> 
> Here is a quick example of what I'm doing.  I've also
> tried replacing $local with the XPATH expression, but
> I still get a RTF.
> 
> <xsl:variable name="local" 
> select="../member[@component=$localComponent]"/>
> <xsl:call-template name="insertAccessRule">
>    <xsl:with-param name="guid" select="current()/access/@guid0"/>
>    <xsl:with-param name="agent"
> select="current()/@agent-ip"/>
>    <xsl:with-param name="src" select="current()"/>
>    <xsl:with-param name="dest" select="$local"/> </xsl:call-template>
> 
> <xsl:template  name="insertAccessRule">
>    <xsl:param name="guid"/>
>    <xsl:param name="agent"/>
>    <xsl:param name="srcNode"/>
>    <xsl:param name="destNode"/>
>    ....
> </xsl:template>
> 
> Thanks
> Charlie