Subject: RE: [xsl] XML 2 XML using XSL,DTD XALAN - JAVA From: "contest.vix" <contest.vix@xxxxxxxxxx> Date: Thu, 25 Nov 2004 14:43:17 -0200 |
Hi, thanks for the tip. I'm using Jaxp, with Xalan 2.6.0, and the transformation result is stored in a DOMResult object(I tryed to obtain de DocType like this: ((Document) result.getNode()).getDoctype(), it returns null even with the output property of the XSL indicating the correct location of the DTD file, besides it even keep the XSL encoding). Do you have any ideia of what is going on?I don't know why the result Dom tree doesn't have the DTD and encoding desclared in the XSL file... So, If I use XSL 1.0,Will I have to parse the result DOM tree again? The code that I use to transform is: -------begin code public Document Transform(Document DOM, String XSlFileName) throws Exception{ TransformerFactory transformerFactory = null; Transformer transformer = null; DOMResult result = null; StreamSource oLocFonteAqruivoXsl = new StreamSource(new FileInputStream(XSlFileName)); transformerFactory = TransformerFactory.newInstance(); result = new DOMResult(); transformer = transformerFactory.newTransformer(new StreamSource(new FileInputStream(XSlFileName))); transformer.transform(new DOMSource(DOM), result); return ((Document) result.getNode()); } --------end code thanks a lot, Roger. > > > Hi, > > thanks for the tip. > > The only way to validade the result DOM tree is to parse it > > again? The XSL that I'm using has the output property below: > > > > doctype-system="../DTD/MyDTD.dtd"/> > > > > Even with this, the result DOM tree doesn't have a DocType > > with it. Does anyone knows why? I tryed to setup the DocType > > by code: > > Transformer.setOutputProperty(OutputKeys.DOCTYPE_SYSTEM,"MyDTD.dtd"); > > > > Even with this, the resulting DOM tree doesn't have a DocType wiht it. > > > You will need give some more information: > > What processor are you using? > > How are you creating the 'result DOM' - ie a DOMResult? > > How are you viewing the result to decide that it doesn't contain the > doctype? > > Ultimately the answer is 'yes' that the only XSLT 1.0 way to validate > the result is to parse it again. With 2.0 and a schema aware processor > (Saxon 8.x) you should be able to provide a result schema and Saxon will > flag up (halt or warn... not sure?) at transform time any non-valid > output. > > cheers > andrew > __________________________________________________________________________ Acabe com aquelas janelinhas que pulam na sua tela. AntiPop-up UOL - I gratis! http://antipopup.uol.com.br/
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