Subject: RE: [xsl] XML 2 XML using XSL,DTD XALAN - JAVA From: "Michael Kay" <mike@xxxxxxxxxxxx> Date: Thu, 25 Nov 2004 17:32:28 -0000 |
As I said before, xsl:output defines what happens when the result document is serialized, and you are not doing any serialization, so it should be ignored. Michael Kay http://www.saxonica.com/ > -----Original Message----- > From: contest.vix [mailto:contest.vix@xxxxxxxxxx] > Sent: 25 November 2004 16:40 > To: xsl-list > Subject: RE: [xsl] XML 2 XML using XSL,DTD XALAN - JAVA > > Hi, > thanks for the tip. > I'm using Jaxp, with Xalan 2.6.0, and the transformation > result is stored in a DOMResult object(I tryed to obtain de > DocType like this: ((Document) > result.getNode()).getDoctype(), it returns null even with the > output property of the XSL indicating the correct location of > the DTD file, besides it even keep the XSL encoding). Do you > have any ideia of what is going on?I don't know why the > result Dom tree doesn't have the DTD and encoding desclared > in the XSL file... > > So, If I use XSL 1.0,Will I have to parse the result DOM tree again? > > The code that I use to transform is: > -------begin code > public Document Transform(Document DOM, String > XSlFileName) throws Exception{ > TransformerFactory transformerFactory = null; > Transformer transformer = null; > DOMResult result = null; > StreamSource oLocFonteAqruivoXsl = new > StreamSource(new FileInputStream(XSlFileName)); > > transformerFactory = TransformerFactory.newInstance(); > result = new DOMResult(); > > transformer = > transformerFactory.newTransformer(new StreamSource(new > FileInputStream(XSlFileName))); > transformer.transform(new DOMSource(DOM), result); > > return ((Document) result.getNode()); > } > --------end code > > thanks a lot, > Roger. > > > > > > Hi, > > > thanks for the tip. > > > The only way to validade the result DOM tree is to parse it > > > again? The XSL that I'm using has the output property below: > > > > > > doctype-system="../DTD/MyDTD.dtd"/> > > > > > > Even with this, the result DOM tree doesn't have a DocType > > > with it. Does anyone knows why? I tryed to setup the DocType > > > by code: > > > > Transformer.setOutputProperty(OutputKeys.DOCTYPE_SYSTEM,"MyDTD.dtd"); > > > > > > Even with this, the resulting DOM tree doesn't have a > DocType wiht it. > > > > > > You will need give some more information: > > > > What processor are you using? > > > > How are you creating the 'result DOM' - ie a DOMResult? > > > > How are you viewing the result to decide that it doesn't contain the > > doctype? > > > > Ultimately the answer is 'yes' that the only XSLT 1.0 way > to validate > > the result is to parse it again. With 2.0 and a schema > aware processor > > (Saxon 8.x) you should be able to provide a result schema > and Saxon will > > flag up (halt or warn... not sure?) at transform time any non-valid > > output. > > > > cheers > > andrew > > > > ______________________________________________________________ > ____________ > Acabe com aquelas janelinhas que pulam na sua tela. > AntiPop-up UOL - I gratis! > http://antipopup.uol.com.br/
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